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#1727856 - 12/31/11 10:37 AM
I need help with lumens...
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Stoner
  
Registered: 12/20/11
Posts: 431
Loc: Yes
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A question, I've been pondering for a while, for you to consider:
Background:
Let's say that our one thousand watt HPS puts out one hundred thousand lumens (probably low but I like to keep things simple)
By definition lumen ratings are based/taken one foot from the source so (according to that inverse square law thingy), at twice that distance, two feet from the source, the lumens drop to twenty five thousand lumens. (one divided by (the inverse thing), two feet (twice the original distance from the source), squared (four) equals one quarter or twenty five percent, a loss of seventy five percent at twenty four inches. At three times the distance (three feet), there are 1/9 lumens or 1/(3 squared) for a total of eleven thousand one hundred eleven lumens.At four times the distance (four feet), there are 1/16 lumens or 1/(4 squared) for a total of six thousand two hundred fifty lumens, etc.
Now for my question, what happens when you move closer to, rather than further away from, the source?
Let's say I have eighteen, sixty-five watt CFL bulbs (total eleven hundred seventy watts going in, slightly more than the example above) rated at thirty six hundred lumen each, for a total of sixty four thousand eight hundred lumen.
Now, if I move these lights to six inches from the plant (one half the distance at which lumen measurements are taken), would the formula then be the same only with a distance halved instead of doubled, tripled, etc.?
Due to the definition of a lumen, I cannot decrease the distance between the source and receiver below one foot and still call it a lumen. Or can I?
In this case the math indicates that at six inches(1/(.5 X .5)) X lumen rating, my sixty four thousand eight hundred lumens are equal to two hundred fifty nine thousand two hundred "perceived" lumens. Wow, I gotta be wrong somewhere, how about it guys?
Let's see what happens (if my assumptions are correct) when the bulb is three inches (1/4D) from the plant... Wow again, sixteen times the rating equals one million thirty-six thousand eight-hundred "perceived" lumens.
What an I doing wrong here? Anyone?
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#1728377 - 01/04/12 03:29 PM
Re: I need help with lumens...
[Re: my1952HD]
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Stoner
  
Registered: 12/20/11
Posts: 431
Loc: Yes
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Hey everyone, I found my answer and my thinking was correct At 1/2 the distance, six inches, the intensity is multiplied by four times. At 1/3 the distance, four inches, the intensity is multiplied by nine times. At 1/4 the distance, three inches (well within my range), the intensity is multiplied by sixteen times. This means that a single sixty five watt CFL putting out thirty six hundred lumen at one foot, puts out fifty seven thousand lumen at three inches, and I've got twelve bulbs, so that's six hundred ninety one thousand two hundred lumen total! Please take a moment and watch this. Rad 7 Inverse Square LawAll though this example is for radiation, another form of light, and is measured in rems, which are based on a point one meter from the source, the same law applies to lumen, based at one foot from the source. Now I'll go fire one up and shut up for a while... Sorry for being a jerk...
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#1742844 - 05/13/12 06:01 AM
Re: I need help with lumens...
[Re: McLovin']
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Veteran
 
Registered: 02/24/11
Posts: 1381
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and I'm sure everyone knows that plants don't use lumens, it's all about Photosynthetically Active Radiation which was where your link led to radiation but hats off for some research though I think this point is being overlooked also. I understand what he is talking about but growing under cfl's when compared to the hid family is like trying to grow outside with a canopy over your garden with holes in it. Photosynthisis, lumens, and intensity are all still there but only for a little area under the hole. The rest of the garden suffers. Sadly all the research in the world does not hide the fact that the hid family has no real competition yet. Remember KISS?
Edited by Sir.Ganga (05/13/12 06:03 AM)
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#1742859 - 05/13/12 10:35 AM
Re: I need help with lumens...
[Re: Sir.Ganga]
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Old hand
 
Registered: 08/17/09
Posts: 1109
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Hey 1952HD, you read my ridiculously long posts in that cfl grow thread, I want to get into that briefly if I can. You wrote that "I seem to understand it", referring to the inverse square law. What did you think about my mention of a modern car projector headlight? Do you dispute my claim that the inverse square law is not applicable to that? Do you dispute my claim that with any type of reflector, the inverse square law does not strictly apply?
We're looking at this almost the exact opposite way. You're looking at lumens and distances between the bulbs and plants, with no mention of reflectors, I'm looking at wattage vs plant surface area, and trying to design an overall system that will get the light to the plant the best way.
If you want to see a pic of my setup with the reflector walls, it's in the hydro section, "dwc setup, couple pics".
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9/11 was an inside job. Rights are only protected by force, so be strong. End the Fed.
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